A random sample of adult men was asked if they would return the money if they found a wallet on the street. Of 143 men, 29 said they would. The true proportion of all adult men who would return the money is 18%. Which of the following do you expect would accurately describe the sampling distribution of the sample proportion of men would return money from a found wallet? Select one or more:
a. The mean of the sampling distribution will be equal to 0.18.
b. The mean of the sampling distribution will be equal to 0.2028.
c. The sampling distribution would be approximately standard normal.
d. The sampling distribution will be skewed right.
e. The sampling distribution will be skewed left.
f. The sampling distribution will be approximately normal.
g. The standard deviation of the sampling distribution will be 0.0336.

b. The mean of the sampling distribution will be equal to 0.2028.

f. The sampling distribution will be approximately normal.

g. The standard deviation of the sampling distribution will be 0.0336.

Step-by-step explanation:

We use the Central Limit Theorem to solve this question.

Central Limit Theorem:

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean and standard deviation .

The sample proportion being approximately normal means that option f. is correct.

Of 143 men, 29 said they would.

This means that

This means that option b is correct.

g. The standard deviation of the sampling distribution will be 0.0336.

Lets find the standard deviation.

Sample of 143, so

So option g. is correct.

answer is c

step-by-step explanation:

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐