What is the equation of the line that passes through the point (-7, 2) and has a
slope of -1?

Point-Slope Form: y-2 = -1(x+7) Slope-Intercept Form: y = -x-5 Standard Form: x+y = -5

Step-by-step explanation:

Because we were giving the slope and a point, we can write this in point-slope form.

Point-Slope Form: y-y1=m(x-x1)

Substitute the point and slope into (x1,y1) and m: y-2 = -1(x-(-7))  

y-2 = -1(x-(-7))  = y-2 = -1(x+7)

y-2 = -1(x+7)

If want in slope-intercept form (y=mx+b),

y-2 = -1(x+7)

y-2 = -1x-7

y = -1x-5 = y = -x-5

To convert to standard form (ax+by=c)

y = -x-5

y+x = -5 = x+y = -5

Hoped I've helped! Good Luck!

answer: the answer is 5/22

step-by-step explanation: if you subtract 17 from 22 the answer is 5 therefore the remainder of students are female

circle area = pi * radius^2

if diameter = 10 then radius = 5

circle area = pi * 5^2

circle area = pi * 25

circle area = 78.5398163397 square units

step-by-step explanation: