Please answer fast The half-life of carbon-14 is 5,730 years. Suppose a fossil is found with 30 percent as
much of its carbon-14 as compared to a living sample. How old is the fossil?

28,993 years
9,955 years
2,899 years
996 years

Step-by-step explanation:

0.5^(t/5730) = 0.30

2^(-t/5730) = 0.30

-t/5730 = log₂0.30

t = -5730 log₂0.30 ≈ 9953 years

step-by-step explanation:

once you graph it hit 2nd (the blue button) and graph

that takes you to a table of coordinates

on the left is x coordinates and on the right is y coordinates and an empty box

(you may have to scroll up/down in order to get ( x, 0)

15%

step-by-step explanation:

use the table and count the number of guesses that has two correct answers.

the following are two correct answers

10010, 01100, 11000

a total of 3 numbers having 2 correct guesses out of 20 questions.

probability of getting 2 correct guesses = the number of questions getting 2 correct answers / total number of questions.

= 3/20

to convert it into percent multiply by 100, we get

= 3/20 * 100

= 15%

the answer is 15%

you.