Chord AC intersects chord BD at point P in circle Z. AP=12 m DP=5 m PC=6 m What is BP?

BP = 14.4

Step-by-step explanation:

Given 2 chords intersecting inside a circle, then

The products of the measures of the parts of one chord is equal to the product of the measures of the parts of the other chord, that is

BP × DP = AP × PC , that is

BP × 5 = 12 × 6

5BP = 72 ( divide both sides by 5 )

BP = 14.4

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.

answer: 75°

step-by-step explanation:

∠esk is the supplement of ∠edk, so is 100°. ∠esd = 1/2·arc ed, so is 25°.

since ∠esk = ∠esd + ∠dsk

you have 100° = 25° + ∠dsk . .

fill in known values 75° = ∠dsk . . . . .

subtract 25°

step-by-step explanation: