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Mathematics, 21.02.2021 07:10 chris018107

The inverse of f(x) = x2 – 3 is f-() = x2 +3
:: - (2) = V2 + 3
:: f-(x) = V2 - 3
:: f-1 (2) = 1 - 3

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The inverse of f(x) = x2 – 3 is f-() = x2 +3
:: - (2) = V2 + 3
:: f-(x) = V2 - 3
...
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