You have a bag of chocolate candy. Ten of them are red, 7 are brown, 12 are green, and 9 ore blue. What is the probability that you pick a red candy, given that
you have already picked o red candy and have not replaced it?

5/19

Step-by-step explanation:

You get this by adding all the marbles to find the total number of marbles. 10+7+12+9, which equals 38.

You have 10 red marbles out of 38 total, so that is represented by 10/38

And divided them by 2 and in your simplified fraction it is 5/19

if this helps please could you please give brainilst? and have a great day

A

Step-by-step explanation: 10/37

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

answer: asdfghjkl,mnbv

step-by-step explanation: