What is an equation of the line that passes through the points (-6, -2) and
(6,8)?

y=5/6x+b

Step-by-step explanation:

use formula (y2-y1)/(x2-x1) to look for the slope:

(8-(-2))/(6-(-6))

=10/12

=5/6 (simplified)

then, use the formula y=mx+b to get the equation by substituting m and x, y to either (-6, -2) or (6, 8):

8=5/6(6)+b

8=5+b

3=b (subtract 5 on both sides)

equation:

y=5/6x+3

the correct answer is 45x

9×5=45 then add the x

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²