X^2+10x+22=13 1. Rewrite the equation by completing the square your equation should look like (x+c)^2 = d or (x-c)^2=d 2. What was the solution to the equation?

(x+5)² = 16

Solution: -1 and -9

Step-by-step explanation:

Given the quadratic equation X^2+10x+22=13

Subtract 22 from both sides

X^2+10x+22-22=13-22

x^2+10x = -9

Complete the square

Add the square of half of coefficient of x to both sides

coefficient of x = 10

half of coefficient of x = 10/2 = 5

square of half of coefficient of x= 5² = 25

Add 25 to both sides

x²+10x + 25 = -9+25

(x+5)² = 16

Hence the required equation is (x+5)² = 16

(x+5)² = 16

square root both sides

√(x+5)² = √16

x+5  = √16

x +5 = ±4

x = +4 - 5 and -4-5

x = -1 and -9

Hence the solution to the equation is -1 and -9

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584

table 3 represents a direct variation function. : )