B is the midpoint of AC and AC=8r-20,and AB=3x-1
Find BC

BC = 26

Step-by-step explanation:

since B is the midpoint of AC, then AB = BC

AC = 8x - 20 & AB = 3x - 1

AC = AB + BC or 2AB

8x - 20 = 2(3x - 1)

8x - 20 = 6x - 2

subtract 6x form each side

2x - 20 = -2

add 20 to each side

2x - 20 + 20 = -2 + 20

2x = 18

x = 9

BC = 3x - 1

BC = 27 - 1

BC = 26

AC = 52

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

df =

both have same length