14. A right cone has a height of 14 in and a base diameter of 17 in. a Sketch and label a diagram of the cone
b. Determine the area of the lateral surface of the cone, to the nearest square inch​

Given:

The height of a right cone = 14 in

Base diameter = 17 in

To find:

The diagram of the cone and its lateral surface area.

Solution:

(a)

The diagram of a right cone with height 14 in and base diameter of 17 in is shown below.

Diagram is not to scale.

(b)

We know that lateral surface of the cone is

             ...(i)

Where, r is the base radius, h is vertical height and l is the slant height of the cone.

Base radius of the cone =

Now,

Putting r=8.5, h=14 and π=3.14 in (i), we get

Therefore, the lateral surface area of the cone is 437 sq. inches.

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it