Write an equation of the line that passes through (-4,-1) and is parallel to the y=4/3x+6​

y = (4/3)x -2/3

Step-by-step explanation:

y=4/3x+6 is clearer if written as y = (4/3)x + 6.  A line parallel to this has the same slope (4/3) but a different constant.

Starting with y = (4/3)x + C, substitute -4 for x and -1 for y and calculate C:

-1 = (4/3)(-4) + C, or

-1 = -(1/3) + C, or

-2/3 = C

Thus, substituting -2/3 for   C   in   y = (4/3)x + C, we get:

y = (4/3)x -2/3

a. she will receive a refund of $278.

step-by-step explanation:

1. 16.64

a^2+b^2=c^2

pr^2=pq^2+qr^2

pr^2=14^2+ 9^2

pr^2=196+81

pr= sqr root of 277

16.64

2. 11.31

c^2-a^2=b^2

18^2- 14^2=b^2

b^2=324-196

b=sqr root of 126

b=11.31

hope it ! (btw im in connections academy to, good luck! )