Joe and Brody order some food for their families. Joe orders 2 chicken dinners and 3 sides for $34.50. Brody orders 3 chicken dinners and 2 sides for $43.00. All the dinners cost the same, and all the sides cost the same.
What is the cost of 1 side?

A $2.75
B. $3.00
C. $3.25
D. $3.50

D

Step-by-step explanation:

If Joe orders 2 chicken dinners and 3 sides for $34.50, then you have to multiply 3.50 by 3 to get the ammount that the dinners cost.

3.50x3 = 10.50

Next, you have to subtract 10.50 from 34.50 to get the cost of just the 2 dinners.

34.50 - 10.50 = 24.00

Now, divide 24 by 2 to get the cost for 1 dinner.

24/2 = 12

Since Brody ordered 2 sides, you have to subtract 3.50x2 = 7 from 43 to get the total of his dinners.

43 - 7 = 36.

Now we can check our answer. Since 1 dinner costs $12, we can multiply 12 by 3 to get 36, which is the exact same number as the one we just figured out. So, each side costs 3.50.

(You can also multiply 12 by 3.50 to get 43, which was the total cost of Brody's order.)

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17

4.

step-by-step explanation:

it have the same area.brainliest