PLEASE HELP I WILL GIVE BRAINALIST AB contains points (4, 2) and (−1, −8). What is the equation of the line parallel to AB that contains point (0, 5)?

9514 1404 393

  y = 2x +5

Step-by-step explanation:

We can use the slope formula to find the slope of AB, which is the same as the slope of the parallel line. Then, we can use the point-slope equation for a line to find the desired equation.

  m = (y2 -y1)/(x2 -x1)

  m = (-8 -2)/(-1 -4) = -10/-5 = 2

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  y -y1 = m(x -x1) . .  point-slope form of equation for a line

  y -5 = 2(x -0) . . . . fill in m=2, (x1, y1) = (0, 5)

  y = 2x +5 . . . . . . . rearrange to slope-intercept form

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

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step-by-step explanation: