5x^2-41x+8=0 please helpp

Use the quadratic formula

=

−

±

2

−

4

√

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac​​

Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.

5

2

−

4

1

+

8

=

0

5x^{2}-41x+8=0

5x2−41x+8=0

=

5

a={\color{#c92786}{5}}

a=5

=

−

4

1

b={\color{#e8710a}{-41}}

b=−41

=

8

c={\color{#129eaf}{8}}

c=8

=

−

(

−

4

1

)

±

(

−

4

1

)

2

−

4

⋅

5

⋅

8

√

2

⋅

5

2

Simplify

3

Separate the equations

4

Solve

Solution

=

8

=

1

5

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