Graph a triangle (STU) and reflect it over the y-axis to create triangle S′T′U′. Describe the transformation using words. Make sure you refer to the characteristics and the coordinates.
Draw a line segment from point S to the reflecting line, and then draw a line segment from point S′ to the reflecting line. What do you notice about the two line segments you drew? Do you think you would notice the same characteristics if you drew the line segment connecting T with the reflecting line and then T′ with the reflecting line? How do you know?

got this question wrong would like to know how to do it

The reflection of a preimage (x, y) across the line y = x gives the image (y, x)

Therefore, the the coordinates of the points L, M, and N interchange to give an image of the triangle that is apparently rotated 90° clockwise, on the opposite quadrant and equidistant from the line y = x

2) Where the line segment drawn from point L to the reflecting line is horizontal, and the line segment drawn from point L to the reflecting line is horizontal, the two line segment will be of the same length and separated vertically separated vertically by a distance equal to the sum of the absolute values of the x and y coordinates of the point L

When the line segment from point L is drawn perpendicular to the reflecting line, the line segment from point L' drawn perpendicular to the reflecting line will meet the the perpendicular line segment at the same point of intersection of the line from the point L and the reflecting line

3) Yes

4) This is so because, reflection of a preimage unto an image is a form of rigid transformation, therefore, the effect of the transformation operation will be similar when each point is individually considered.

Step-by-step explanation:

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.

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step-by-step explanation: