Find the value of x 3x+6 41 6x-5 4x+7 62 7x-11

13

Step-by-step explanation:

Simplifying

3x + 6 + 7x + -11 + 41 + 62 + 6x + -5 + 4x + 7 = 360

Reorder the terms:

6 + -11 + 41 + 62 + -5 + 7 + 3x + 7x + 6x + 4x = 360

Combine like terms: 6 + -11 = -5

-5 + 41 + 62 + -5 + 7 + 3x + 7x + 6x + 4x = 360

Combine like terms: -5 + 41 = 36

36 + 62 + -5 + 7 + 3x + 7x + 6x + 4x = 360

Combine like terms: 36 + 62 = 98

98 + -5 + 7 + 3x + 7x + 6x + 4x = 360

Combine like terms: 98 + -5 = 93

93 + 7 + 3x + 7x + 6x + 4x = 360

Combine like terms: 93 + 7 = 100

100 + 3x + 7x + 6x + 4x = 360

Combine like terms: 3x + 7x = 10x

100 + 10x + 6x + 4x = 360

Combine like terms: 10x + 6x = 16x

100 + 16x + 4x = 360

Combine like terms: 16x + 4x = 20x

100 + 20x = 360

Solving

100 + 20x = 360

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-100' to each side of the equation.

100 + -100 + 20x = 360 + -100

Combine like terms: 100 + -100 = 0

0 + 20x = 360 + -100

20x = 360 + -100

Combine like terms: 360 + -100 = 260

20x = 260

Divide each side by '20'.

x = 13

Simplifying

x = 13

b. an equilateral triangle inscribed in a circle

step-by-step explanation:

we are given the figure of two circles having a triangle inside.

now, we know that,

"when a figure is lying inside an another figure, then the outside figure is known as circumscribed figure and the figure lying inside is referred to as the inscribed figure".

as we see that, the circles are containing the triangle completely.

thus, the circles are the circumscribed figures and the triangle is the inscribed figure.

hence, we get, 'an equilateral triangle is inscribed in a circle'.

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.