Find the particular solution of the differential equation?
/=5^3+9^2, when =1, =8

Step-by-step explanation:

f'(2) = 3(2)2-6(2)+C

      = 3(4)-12+C

      = C

      = 3

We have f'(x) = 3x2-6x+3. Then,

f(x) = x3-3x2+3x+D

But f(2) = 1, so

f(2) = 23-3(2)2+3(2)+D

      = 8 - 12 + 6 + D

      = 2 + D

      = 1

so D = -1. We have f(x) = x3-3x2+3x-1

+25 = x

step-by-step explanation:

here x is the hypotenuse of a right triangle whose legs are 7 and 24.   by the pythagorean theorem, 7² + 24² must equal x²:

x² = 49 + 576 = 625.   thus, x = +√625 = +25 = x