Las notas de 35 alumnos en el examen final de estadística, calificado del 0 al 10, son las siguientes: 0; 0; 0; 0; 1; 1; 1; 1; 2; 2; 2; 3; 3; 3; 3; 4; 4; 4; 4; 5; 5; 5; 5; 6; 6; 6; 7; 7; 7; 8; 8; 8; 9; 10; 10.

Con los datos obtenidos, elaborar una tabla de frecuencias con 5 intervalos o clases.

Luego realiza la representación gráfica en base a la tabla:

*Histograma

*Polígono de frecuencia

*Ojiva​

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

only 10/60 isn't equivalent

hope this : )

step-by-step explanation:

its 512 because parenthesis and to the 2nd power is 512 so it will be 512