Find an equation of the line that passes through (2,-3) and is perpendicular to the line 2x-y=10.

l#First find the gradient first, remember the formula of equation of the line is y = mx + c where m is the gradient.

2x - y = 10

-y = -2x + 10

y = 2x - 10

#So the gradient is 2, now find the equation of the line

y - y1 = m(x - x1)

y - (-3) = 2(x - 2)

y + 3 = 2x - 4

y = 2x - 4 - 3

y = 2x - 7

2y = x - 7/2

-x + 2y = -7/2

x - 2y = 7/2

8

step-by-step explanation: