What is the center of the circle for this equation:
(x - 6)² + (y + 9)² = 25

Step-by-step explanation:

Knowing this information, we can deduce that the center of the circle is at

(

6

,

−

2

)

, and the radius measures 3 units.

x

=

9

is a vertical line, while the circle will extend equal length in all direction, in function of it's radius. Looking at the centre and adding 3 to the x value, we get the point

(

9

,

−

2

)

. This point doesn't only lie on the circle; it also lies on the line

x

=

9

. Furthermore, this is the furthest possible distance from the center, so the line will only pass through this one point. Therefore, we can state that the line x = 9 is tangent to

(

x

−

6

)

2

+

(

y

+

2

)

2

=

9

If you graph the circle and the line you will get the same answer.

idk

step-by-step explanation:

i don't know

the square root of what number? if you add that, then someone will probably answer the question.