Translate A(-3,-3) B ( 4,-5) C (0,0) 4 units left and 2 units down write the ordered pairs of the image

The ordered pairs of the image of the points A(-3,-3), B( 4,-5), and C (0,0) will be:

The graph is also attached to illustrate the concept of translation.

Step-by-step explanation:

Given the points

Given that we need to translate the points 4 units left and 2 units down.

It means the original points need to horizontally move 4 units to the left i.e. subtracting 4 units from the x-coordinate and vertically move 2 units down i.e. subtracting 2 units from the y-coordinate.

Thus,

The rule/formula of translation can be expressed as:

P(x, y) → P'(x - 4, y - 2)

Here:

P is the original point and P' is the image of the original point P.

Now, translating the given points using the same rule of the translation.

A(-3, -3) → A'(-3 - 4, -3 - 2) → A'(-7, -5)

B(4, -5) → B'(4 - 4, -5 - 2) → B'(0, -7)

C (0,0) → C'(0 - 4, 0 - 2) → C'(-4, -2)

Therefore, the ordered pairs of the image of the points A(-3,-3), B( 4,-5), and C (0,0) will be:

The graph is also attached to illustrate the concept of translation.

i dont know sorry

step-by-step explanation:

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)