Consider the following data: 3.2, 3.5, 3.5, 3.5, 3.6, 3.7, 3.7, 3.8, 3.8, 3.9, 3.9, 3.9, 4, 4, 4, 4.1, 4.1, 4.2, 4.2, 4.3, 4.4, 4.4, 4.6, 5.1, 5.1. If the second class interval is 3.7-4.1: What is the Class Width of each class? [ Select ] What is the Upper Class Limit of the third class? [ Select ] What is the Upper Class Boundary of the fourth class? [ Select ] What is the frequency of the third class? [ Select ] What is the Relative Frequency of the second class?

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

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step-by-step explanation:

well what did you do it matters what you did : )

step-by-step explanation:

answer is 8x+24

area of vanessa's patio = length × width

given, length = (3x² + 5x + 10)

width = (x² - 3x - 1)

area of vanessa's patio = (3x² + 5x + 10)(x² - 3x - 1)

= 3x²(x² - 3x - 1) + 5x(x² - 3x - 1) + 10(x² - 3x - 1)

= 3x⁴ - 9x³ - 3x² + 5x³ - 15x² - 5x + 10x² - 30x - 10

= 3x⁴ - 4x³ - 8x² - 35x - 10

hence, expression of vanessa's patio = (3x⁴ - 4x³ - 8x² - 35x - 10)