Three boats are at sea Jenny one(j1) Jenny two(j2) and Jenny three (j3). The crew of j1 can see both j2 and j3 (they create a triangle). The angle created at j1 is 45°. If the distance between j1 and j2 is 2.7 miles and the distance between j2 and j3 is 4.2 miles, what is the distance between j1 and j3 to the nearest tenth of a mile?

Step-by-step explanation:

You know an angle, the side opposite the angle, and the side between them.

Use the Law of Sines.

j3 = arcsin(2.7sin(j1)/4.2) ≅ 27.0°

j2 = 180°-j1-j3 ≅ 108.0°

x = distance from j1 to j2

= 4.2sin(j2)/sin(j1)

≅ 5.7 miles

the cat is blue because the probability of extension towards the prefix of the diameter of the circle could only mathematically equal to the sum of the roots of the carrots from   your garden.

step-by-step explanation:

the answer is b.)

< 1=< 2