A box contains 6 red pencils and 8 blue-pencils. A pencil is chosen at random and not replaced. A second pencil is then chosen at random. Calculate the probability that at least one
of the pencils is red

There are 14 pencils and 8 are blue

The probability of picking blue in the first pick = 8/14 =4/7.

The probability of picking blue in the second pick = 7/13 (as no replacement was there).

There are 14pencils and 6 are red.

The probability of picking red in the first pick = 6/14 =3/7

The probability of picking red in the second pick = 5/13. (as no replacement was there).

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,