If the sum of 2 digits no. is 9 and their differenc is 1 find te no.​

Let the ten's digit no. be x and one's digit no. be y.

So the no. will be = 10x+y.

Given : x+y=9(I)

9(10x+y)=2(10y+x) ⇒88x−11y=0 (II)

On solving I and II simultaneously you will get x=1 and y=8.

Therefore your desired no. is 18.

Step-by-step explanation:

Hope it is helpful

75 tickets have been sold so far.

step-by-step explanation:

in this question it is clearly mentioned that 45 children's tickets have been sold and this number is 60% of the total tickets sold.

now let's assume the total number of tickets sold be x.

then 60% of x = 45

⇒

⇒ x(.6) = 45

by dividing with .6 on both the sides of the equation

⇒ x = 75

therefore 75 tickets have been sold so far.

not sure but it may be b, as i said i'm not sure.