CONSTRUCT ∆PQR IF PQ = 5CM , ˂PQR =1150, ˂PQR =5

Hai :>

ya answer is:

\Delta PQR if PQ = 5 cm, m\angle PQR = 105^{\circ} and m\angle QRP = 40^{\circ}:

the sum of angles of a triangle is 180 degrees. Given angles PQR and QRP, so the angle QPR= 180-(105+40)=35 degrees

1. Draw the line PQ=5 cm  

2. At Q making an angle 105 degrees with PQ draw a line QY

3. At P making an angle 35 degrees with PQ draw a line PX

4. The lines PX and QY intersect at R ( in case the drawn line PX or QY is small extend it to intersect each other)

PQR is the required triangle

hope that this helps ya! Happy Valentines Day! :>

☁ floofy-cloud ☁

a. -0.3 > -0.33