How do i write an equation that goes through the line (-10,8) with a slope of 6

y = 6x + 68

Step-by-step explanation:

The form is y=mx+b, where m is the slope and b is the y-intercept.

We know that the slope is 6, so we substitute it for m in the equation:

y=6x+b

If we look at the graph shown below, we see that (-10, 8) has been plotted (the little dot).

Let's pretend there's an invisible 1 below 6: This is our slope. We can do rise over run: . 6 is the rise and 1 is the run.

If we look at the second picture, we went up 6 spaces and ran 1 space. We would keep doing this until the line hits the y-axis, which is the y-intercept. The y-intercept is 68. So the equation is

y = 6x + 68

the answer will be b x² +x-1

step-by-step explanation:

answer would be 8.64 or s = 11π/4 inches

step-by-step explanation:

s = r θ  

where s = arc length  

r = radius = 3 inches  

θ = central angle in radians = ( π /180)*165  

s = 3(π/180)*165  

= 8.64 inches