A ball is thrown vertically downwards at 2 m/s from the top of a high building. Given that the distance, s meters, travelled by the ball in the first t seconds ofter being thrown is s = 2t + 5t^2 a) Calculate
i) the distance, in meters, travelled by the ball in the first 3 seconds.
ii)the distance, in meters travelled by the ball in the third second.
iii) the time, in second, take to travel in first 7 meters.
b)i) Obtain an expression, in terms of t, for the speed, in m/s,
at which the ball is traveling t seconds after being thrown.
ii) Calculate the speed, in m/s, of the ball 2 1/4 seconds after being thrown.
iii) Find the time, in seconds, taken to reach a speed of 17 m/s.
c) Find the acceleration, in m/s^2, of the ball after t seconds.
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the barter

we have the parent function given by,

1. the function is translated 5 units to the left.

so, we get,   becomes

2. the function is translated 5 units to the right.

so, we get,   becomes

3. the function is translated 5 units upwards.

so, we get,   becomes

4. the function is translated 5 units downwards.

so, we get,   becomes

5. the function is reflected across x-axis.

so, we get,   becomes

6. the function is reflected across y-axis.

so, we get,   becomes .

step-by-step explanation:

mark brainliest.

answer:   expression= p+p*d%

price reduction + sale price = $625

sale price: $p+$p*d%

where d% is the percentage of discount

step-by-step explanation:

original price = p

price went down by $150 price reduction $p*d%

sale price= $ 475

therefore the price before sale is: $625

and the expression that shows the price before sale is: p+p*d%

the answer for your question is

step-by-step explanation: