15 pts + brainliest when ready Gilligan sees a ship coming close to the shore he's standing on. He wants to
determine the distance (SD) from the ship to the shore. He walks 130 ft along the
shore from point D to point C and marks that spot. Then he walks 23 ft further and
marks point B. He turns 90 and walks until his location (point A), point C, and point
S are collinear.

(A) Can Gilligan conclude that triangle ABC and triangle SDC are similar? Why or why
not?

(B) Suppose AB = 90 ft. What can Gilligan conclude about the distance of the ship
from the shore? Explain.

8 2/3 is the answer

step-by-step explanation: just use a calculator

126.66 m²

step-by-step explanation:

the pertinent area formula is a = πr², where r is the radius.

here, a = π(6.35 m)² = 40.32π, or approximately 126.66 m²

df =

both have same length

answer: (-8,4) are the coordinates of a

step-by-step explanation:

let the side of square abcd is x .

thus the area of square abcd is .

now, by the diagram area of triangle ead= 1/2 × ea × ad = 1/2 × ea × x

( because ad is the side of square)

and, according to the question,

the areas of square abcd and right ead are equal.

⇒

⇒ea=2x

thus, ea: ab=2: 1

therefore, point a divides line segment eb into the ratio 2: 1.

⇒ by sectional formula coordinates of a are,

=

=

=(-8, 4)

thus the coordinates of a are (-8,4)