City A City B
55
60
90
95
63
80 85
Noon temperature (in Fahrenheit)
(a) Which city had the highest noon temperature?
'Choose one'
(b) Which city had a larger median noon temperature?
'Choose one
(c) Which city had noon temperatures with a larger
interquartile range (IQR)?
Choose one
(d) Which city had more noon temperatures above 78 °F?
'Choose one'
Explanation
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a. City B

b. City A

c. City A

d. City A

Step-by-step explanation:

a. Max temperature for City A = 84°F

Max temperature for City B = 86° F

Therefore, City B has the highest noon temperature

b. City A median noon temperature = 80°F

City B median noon temperature = 72°F

Therefore, City A has the larger median noon temperature.

c. City A IQR = 83 - 75 = 8

City B IQR = 77 - 70 = 7

Therefore, City A has noon temperatures with a higher IQR

d. The median of City A is greater than 78°F, this means about half of its noon temperature are more than 78°F, therefore, City A had more noon temperatures above 78°F compared to City B.

5 x 14?

im new, sorry if this is wrong.

step-by-step explanation:

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm