Find the 8th term of the geometric sequence whose common ratio is 3/2
and whose first term is 2.

2187/64

Step-by-step explanation:

first term (a) = 2

common ratio (r) = 3/2

8th term (t8) = ?

We know

Tn = ar^ n - 1

t8 = 2 * (3/2)^ 8 - 1

= 2 * 2187/128

= 2187/64

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50