A company that manufactures computer components has a 3% defective rate. If 10 components are randomly selected, find the probability of getting 2 defective components. Binomial Probability Formula: P(x) = nCx px qn-x

The probability of getting 2 defective items

P(X=2) = 0.0317416

Step-by-step explanation:

Step(i):-

Given that size of the components n = 10

Given that the probability of getting the defective item

           p = 3% = 0.03

           q = 1-p =1- 0.03 = 0.97

Let 'X' be a random variable in a binomial distribution

Step(ii):-

The probability of getting 2 defective items

P(X =2) = 45 × 0.000705

P(X=2) = 0.0317416

7. d. 64

8. i. 32

9. c. 125

10. j. none of the above

11. d. 81

12. i. 216

13. e. none of the above

14. g. 240

15. e. none of the above

16. g. 32

17.   e. none of the above