Two trains, Train A and Train B, weigh a total of 389 tons. Train A is heavier than Train B. The difference of their weights is 263 tons. What is the weight of each train? Equation 1: Equation 2: Train A weight: Train B weight:

9514 1404 393

Step-by-step explanation:

The first equation is an expression of the first given relationship:

  A + B = 389 . . . . . . where A and B represents trains weights, respectively

The second equation is an expression of the relationship described in the next two sentences:

  A - B = 263

__

These equations can be solved by adding them together:

  (A +B) +(A -B) = 389 +263

  2A = 652 . . . . . . simplify

  A = 326 . . . . . . . .divide by 2*

  B = 326 -263 = 63

Train A weighs 326 tons.

Train B weighs 63 tons.

* You may notice that this value is the average of the given sum and difference. That observation is true of all "sum and difference" problems.

i need more info. are you looked to see there mph? how much they deliver? how far they go?

step-by-step explanation:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!