Please help ASAP really desperate

Q2 A double - cage of a 3 - phase, 60 - Hz, 4 - pole induction motor have the following equivalent circuit parameters, all of which are phase values referred to the stator and the stator impedance is negligible: cage R '= 0.20 X - 102 Inner cage R, -0.022 XX - 222 1 - Calculate the ratio of torques produced by outer cage and inner cage at starting. 2- If the motor runs at a slip of 3%. and the rotor input phase voltage is 45 V. calculate: a) The rotor current and b) The torque contributed by inner and outer cages. 3- What slip will the torque contributed by the two cages be equal? Outer

m= 3/7

Step-by-step explanation:

I'm assuming the question is solve for the variable, m.

First step is to isolate the variable

In other words, let's move everything (but m) from the left side to the right side

To move 7 to the right side, we can either divide both sides by 7 or multiply both sides by 1/7 (both equal the same thing)

7/3m × 1/7 = 1 × 1/7

1/3m = 1/7

Now we must move 1/3 from the left to the right side

We can use the reciprocal, 3/1, to do this

1/3m × 3/1 = 1/7 × 3/1

m = 3/7

the volume is the product of the area of the base, 3x(3x+4), and the height, 3x-1

step-by-step explanation: