Miranda graphed (y + 1)2 > 6(x - 2). Which could Miranda use to justify that her graph is correct? Check all that apply.
Because only the y quantity is squared, the curve is a parabola.
The parabola opens right because 6 is in front of the x-quantity.
There is a strict inequality so the boundary is included in the solution set.
The shading is outside the parabola because (0,0) satisfies the inequality.
The values subtracted from x and y in the equation are the coordinates of the vertex which
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The correct options that describe the inequality (y + 1)² > 6·(x - 2)

1) Because only the 'y' quantity is squared the curve is a parabola

2) The parabola opens right because 6 is in front of the 'x' quantity

3) The shading area is outside the parabola because (0, 0) satisfies the inequality

4) The values subtracted from 'x', and 'y' in the equation are the coordinates of the vertex

Step-by-step explanation:

The given inequality graphed by Miranda is presented as follows;

(y + 1)² > 6·(x - 2)

By simplification, we get;

Given that the inequality is of the form (y - k)² > 4·p·(x - h), we have;

The curve is a parabola as only the 'y' quantity is squared

-k = 1

∴ k = -1

4·p = 6

∴ p = 6/4 = 3/2 = 1.5

p = 1.5

-h = -2

∴ h = 2

The vertex of the parabola = (h, k) = (2, -1)

The axis of symmetry = The x-axis

p = 1.5 > 0, therefore, the parabola opens right

Therefore, the parabola opens right because 6 is in front of the 'x' quantity

There is a strict inequality therefore the boundary is not included in the solution set

When x = 0 and y = 0, we have;

(y + 1)² > 6·(x - 2)

(0 + 1)² > 6·(0 - 2)

1² > 6 × (-2)

1 > -12, which satisfies the inequality and (0, 0) is on the left and below the vertex, therefore, the shaded area is outside the parabola

The vertex of the parabola given in the form, (y - k)² > 4·p·(x - h), is (h, k), which are the values subtracted from 'x', and 'y' in the equation

Therefore, the vertex of the given parabola, (y + 1)² > 6·(x - 2) = (2, -1)

Because only the y quantity is squared, the curve is a parabola.

The parabola opens right because 6 is in front of the x-quantity.

The shading is outside the parabola because (0,0) satisfies the inequality.

The values subtracted from x and y in the equation are the coordinates of the vertex which

Step-by-step explanation:

edge 2021

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841