If k is the midpoint of, jk=11x-7 and kl=6x+2, find jl

JL = 118/5

Step-by-step explanation:

Because K is the midpoint, we know that JK and KL are going to equal each other because of the Segment Addition Postulate.

JK + KL = JL

So we know that JK = 11x-7 and KL = 6x+2

Now, we solve for X.

11x-7 = 6x+2

In order to get X alone, we must get the X's all to one side and the numbers to one side.

11x-7 = 6x+2

   +7        +7

11x = 6x + 9

-6x   -6x

5x = 9

x = 9/5

Now, we plug X into the equations.

JK = 11x - 7

JK = 11(9/5) - 7

JK = 99/5 - 7

JK = 64/5

KL = 6x + 2

KL = 6(9/5) + 2

KL = 54/5

Now, we add the numbers (fractions, really) together so that we can get the whole value of the line.

64/5 + 54/5 = 118/5

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?