Theresa’s computer at home has 1 terabyte of storage. How many more bits of storage does her computer have than the combined bits available on her family’s phones, tablets, and cloud storage? Type your answer in scientific notation.

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Step-by-step explanation:

To find the difference between one terabyte and the storage available to the other mediums, we would need to know the storage available to those mediums.  They can all have potentially different amounts of storage space, so we have no way to answer that part of the question.

We can however find out how many bits her computer has.  There are two lines of thought  to follow though.  kilo, mega, giga etc each generally note a multiple of 1000 in common terms.  In computer tech though, the number 1024, or 2¹⁰, is often used instead.

Starting with the layman's powers of 10, a terabyte is a thousand gigabytes, which in turn is a thousand megabytes, which is a thousand kilobytes, which is a thousand bytes.

That means that a terabyte stores 1 × 10¹² bytes.  A byte however is eight bits, giving us 8 × 10¹² bits.

Using the nerdier powers of 2 then, a byte is eight bits, so we'll call that 2³.  We then go up by multiples of 2¹⁰.  With the same logic above, a terabyte is 2¹⁰ gigabytes, which is 2¹⁰ megabytes, which is 2¹⁰ kilobytes, which is 2¹⁰ bytes.  Adding the exponents up, then a terabyte would be 2⁴³ bits

So depending on whether you use the powers of ten or powers of 2 conventions, then a terabyte is either 8 × 10¹² bits, or 2⁴³ bits.

If you want to express the latter as a power of ten for proper scientific notation, then it would be 8.796093022208 × 10¹² - a rather useless way of expressing it, but just to cover all bases.

i think you look back at your other questions

this is not the answer but it could help

Step-by-step explanation:

p.s. I HATE MATH : )

q: 92 degrees

hope i ^-^

answer: domain and range mean all possible values of x and y that could be substituted to the inequality. a solution means all possible values that make the inequality statement true. so while the range is still all real numbers, the solution is the shaded area, for which y will always be greater than the line of the function.