Please helpp ah

c. a = 3√2, b = 6√2

#1.First, you find the opposite of the left triangle using sin formula

#2.After you get the opposite, find the b using sin formula and a using tan formula

•Right triangle

Hypotenuse = 6

Adjacent = ?

Opposite = ?

• Left triangle

Hypotenuse = b

Adjacent = a

Opposite = ?

a. adjacent of right triangle

b. hypothenuse of left triangle

#1. Sin(∅)= opposite/hypotenuse

sin(45) = opposite/6

opposite = sin(45) × 6

opposite = 3√2

#2. a. tan(∅) = opposite/adjacent

tan(30) = 3√2 / a

a = 3√2 : tan(30)

a = 3√6

b. sin(∅) = opposite/hypotenuse

sin(30) = 3√2 / b

b = 3√2 : sin(30)

b = 6√2

#and so the a = 3√2 and b = 6√2

#you are welcome

#Moderators please don't be mean, dont delete my answers just to get approval from your senior or just to get the biggest moderation daily rank.

answer: .75 km

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idk

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