Which systems of linear equations have no solution? x + y + z = 1,100
x-2y - Z=-500
2x + 3y + 2z = 2,600

x + y + z = 1,500
X-y-z= -500
2x + y + z = 2,000

x + y + z = 1,400
x-2y - z= -500
2x + 2y + 2z = 2,700

x + y + z = 1,400
-0.5x – 0.5y - 0.5z = -900
2x + 3y + 2z = 3,000

x + y + z = 1,900
X- y - 2z = -2,000
2x + 2y + z = 1,100

x + y + z = 2,400
2x - 2y + 2z = 700
x + 3y + z = 2,400
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all 3 variable systems have solutions if they have 3 "unique" equations which means they are not alike or multiples of one another. #1 has a solution as do they all because you cannot multiple any "one" equation by a number and get another equation in its system.

answer: 140

step-by-step explanation:

so just add all then it will be your answer but i am not pretty sur eif it is but hope this i am here to people

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17