Listed below are the lead concentrations in μ​g/g measured in different traditional medicines. Use a 0.05 significance level to test the claim that the mean lead concentration for all such medicines is less than 14 μ​g/g. Assume that the sample is a simple random sample. 18 11.5 5.5 8.5 5.5 14 11 6 10.5 15.5
Assuming all conditions for conducting a hypothesis test are​ met, what are the null and alternative​ hypotheses?
A.
H0​: μ=14 μ​g/g
H1​: μ>14 μ​g/g
B.
H0​: μ=14 μ​g/g
H1​: μ<14 μ​g/g
Your answer is correct. C.
H0​: μ>14 μ​g/g
H1​: μ<14 μ​g/g
D.
H0​: μ=14 μ​g/g
H1​: μ≠14 μ​g/g
Determine the test statistic.
nothing ​(Round to two decimal places as​ needed.)
Determine the P-value?

the answers c

x=6 and x=3

beep beep imma sheep

hope this !

let me know

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)