Te diagonals of Quadrilateral JKLM intersect at A. If KL ≅ J M , JK≅ L M and KA ≅ M A , which additional statement shows that JKLM is a rhombus? Group of answer choices
JA = LA

JL ⊥ K M

m
KA = KJ

JL ⊥ KM

Step-by-step explanation:

JL ⊥ KM would make the quad a rhombus because JKLM is a parallelogram since opposite sides are congruent.  If the diagonals of a parallelogram are perpendicular, then the quad must be a rhombus.

it would not be increasing by nothing that i can see probably by 25 percent that is all i can sat\y for now if i have any thing else to say i will edit this.

step-by-step explanation:

answer: a

step-by-step explanation: the answer is a due to the rule of symmetry; that a line of symmetry must divide a figure into 2 pieces that are the exact same, only reflected over a line of symmetry. b and c do not have lines of symmetry and would not divide the figure evenly, thus making the answer a.