Susie wants to have at least a 90 average for the year in her algebra class. her current test scores are 85, 100, 86, and 97. what does she need to score on her fifth test to have at least a 90 average?

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!

4+4+2x

or

2x+8

step-by-step explanation:

5/12

step-by-step explanation:

give them both a common denominator so you get 9/12 and 4/12. subtract 9/12 from 4/12 to get 5/12.