Find the maximum and minimum values of the function y=1/2 sin2x

Maximum value equals 1/2

Minimum value equals -1/2

Step-by-step explanation:

The Sin Function when Graphed Shows a Range of [-1 , 1]

apply that on y=1/2 sin2x

y = 1/2 * 1 = 1

y = 1/2 * -1 = -1

so y = 1/2 , -1/2 .

dy/dx = 2 * 1/2 * cos2x

put dy/dx=0

cos2x=0

x= 45, x=135

Apply x values on y=1/2 sin2x

y = 1/2 , -1/2 .

Hope you understand it ^^.

no one knows lol

step-by-step explanation: