In ΔEFG, \overline{EG} EG
is extended through point G to point H, \text{m}\angle EFG = (2x+1)^{\circ}m∠EFG=(2x+1)
∘
, \text{m}\angle FGH = (6x+2)^{\circ}m∠FGH=(6x+2)
∘
, and \text{m}\angle GEF = (x+19)^{\circ}m∠GEF=(x+19)
∘
. Find \text{m}\angle GEF. m∠GEF.

25

Step-by-step explanation:

(6x+2)=(x+19)+(2x+1)

6x+2)=(x+2x)+(19+1)

6x+2=  3x+20

−3x+2= −3x

3x+2= 20

3x=  18

x=  6

m∠GEF = x+19 = (6)+19 = 25  

X+19=(6)+19=25

Step-by-step explanation:

answer:

(-8,7)

explanation:

we know that  

f

(

−

3

)

=

7

therefore, if we wish to get the output as 7, in the function, we need to have our input to be -3.

looking at the function  

f

(

x

+

5

)

, what should the value of x be, such that the input in the function becomes 7?

we simply equate the terms,

x

+

5

=

−

3

x

=

−

8

thus, the point on the new function would be  

(

−

8

,

7

)

22

step-by-step explanation: