Given: \angle BAC \cong \angle ACD∠BAC≅∠ACD and \angle ADB \cong \angle DBC.∠ADB≅∠DBC. Prove: ABCDABCD is a parallelogram.

What are the extra steps?

your answer is a

step-by-step explanation:

4*4*4*4=256

p(x)= 8 x³ - 36 x² + 54 x - 27

q(x) = 2 x -3

you can check your mistake and then you can choose the correct option.

dividend =   8 x³ - 36 x² + 54 x - 27

divisor = 2 x -3

if you want to find quotient, proceed as follows

q(x)= 0

2 x - 3=0

x =

now , i have used division method , to find quotient and remainder