What part of the coordinate plane is equidistant from the points a(-3,2) and b(3,2)?

The y-axis is  equidistant from both points

Step-by-step explanation:

 we know that

The formula to calculate the coordinates of midpoint M between two points is equal to

we have

substitute the values in the formula

see the attached figure to better understand the problem

The y-axis is  equidistant from both points

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

a is the correct