Three vertices of a square are given. find the coordinates of the fourth vertex. (_5, 5), (_5, 2), (_2, 2)

If you plot these points, you can probably see where the missing square corner is. But you might also notice that a square's sides are equal length. Between the first two coordinate pairs, the only thing that changes is the y value, from 5 to 2, or a change of 3. Between the 2nd two coordinate pairs, only the x value changes, from -5 to -2, or a change of 3. So it looks like the sides are 3 units long. The fourth coordinate should be 3 units away on the x coordinate from one "neighbor" and 3 units away on the y coordinate from its other neighbor. But it really would help to sketch it out so you don't get mixed up.
(-2, 5)

Abit confused about what you mean, but i think you might be referring to slope intercept form: y = mx + bin that case b, or the y intercept is already given.(0,-1)find the slope by using the formulay2 - y1/x2 - x1the final slope will be 4/2, equivalent to 2.now your equation should look like thisy = 4/2x -1sorry if this didn’t you out!