What are the zeros of f(x) = x2 + x - 12? O A. x= -4 and x = 3
O B. x=-2 and x = 6
O C. =-3 and x = 4
O D. X=-6 and x = 2

(x+4)(x-3) or A

Step-by-step explanation:

I'm going to assume that you meant to write x² and not x2

which means we have

x²+x-12

and we need to factor this

to do this we need two numbers that add up to 1 (b) but mulitply to -12 (a*c)

our two numbers are

4, -3

Which means the answer is

(x+4)(x-3)

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b