Consider functions f and g. f(x)=log(x-1)
g(x)=1/3x^2-4
Which statement is true about the solutions of the equation ?

A.
The solutions are where the graphs of the functions intersect at x=1 and x~3.642 .
B.
The solutions are where the graphs of the functions cross the x-axis at x=-4 and x~0.422 .
C.
The solutions are where the graphs of the functions intersect at x~-3.464 and x~3.464 .
D.
The solutions are where the graphs of the functions cross the x-axis at x~-3.464 and x~3.642.

aloha~! my name is zalgo and i am here to you out on this amazing day. to answer your question, yes, nonzero numbers can have a greatest common factor and that would be 1. still don't get it? let me considering every number is divisible by 1 and hence every number has 1 as a factor of theirs. so, if 2 nonzero numbers didn't share any gcf (greatest common factor), they would still have a factor in common and that would be 1.

i hope that this ! : p

"stay and stay proud! " - zalgo

(by the way, do you mind marking me as brainliest? i'd greatly appreciate it! mahalo! x3)

(a) common ratio in the given sequence is, 3

(b) push ups will do kendall do on the 20th week

step-by-step explanation:

geometric sequence is a sequence of numbers that follows a pattern were the next term is found by multiplying by a constant called the common ratio(r)

(a)

given the sequence: 6 , 18 , 54 , 162 ,

this sequence is geometric sequence where each term is 3 times the previous term.

therefore,

common ratio(r) = 3.

(b)

a formula for nth term of geometric sequence is given by;

,   where r is the common ratio between the successive terms and is the first term,

to find how many push ups will kendall do on the 20th week.

here. n = 20th term.

in the given sequence first term

then;

simplify:

therefore, push ups will do kendall do on the 20th week

hi,

the area of abcd is 245.

3*24=230

4*94=1039

2*12=24

add all of them up, you get 2450

4 inches will get you 10.16 centimeters, but you can either do 10.1 or round up to 10.2. good luck and hope this : )