Mathematics, 11.02.2021 03:00 datgamer13

Tessa solves the equation below by first squaring both sides of the equation. \sqrt{x^2-3x-6}=x-1 x 2 −3x−6 =x−1square root of, x, squared, minus, 3, x, minus, 6, end square root, equals, x, minus, 1 What extraneous solution does Tessa obtain?

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Tessa solves the equation below by first squaring both sides of the equation. \sqrt{x^2-3x-6}=x-1 x...

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Tessa solves the equation below by first squaring both sides of the equation. \sqrt{x^2-3x-6}=x-1 x 2 −3x−6 ​ =x−1square root of, x, squared, minus, 3, x, minus, 6, end square root, equals, x, minus, 1 What extraneous solution does Tessa obtain?​

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Tessa solves the equation below by first squaring both sides of the equation. \sqrt{x^2-3x-6}=x-1 x 2 −3x−6 =x−1square root of, x, squared, minus, 3, x, minus, 6, end square root, equals, x, minus, 1 What extraneous solution does Tessa obtain?